p^2+p=2

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Solution for p^2+p=2 equation:


Simplifying
p2 + p = 2

Reorder the terms:
p + p2 = 2

Solving
p + p2 = 2

Solving for variable 'p'.

Reorder the terms:
-2 + p + p2 = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + p + p2 = 0

Factor a trinomial.
(-2 + -1p)(1 + -1p) = 0

Subproblem 1

Set the factor '(-2 + -1p)' equal to zero and attempt to solve: Simplifying -2 + -1p = 0 Solving -2 + -1p = 0 Move all terms containing p to the left, all other terms to the right. Add '2' to each side of the equation. -2 + 2 + -1p = 0 + 2 Combine like terms: -2 + 2 = 0 0 + -1p = 0 + 2 -1p = 0 + 2 Combine like terms: 0 + 2 = 2 -1p = 2 Divide each side by '-1'. p = -2 Simplifying p = -2

Subproblem 2

Set the factor '(1 + -1p)' equal to zero and attempt to solve: Simplifying 1 + -1p = 0 Solving 1 + -1p = 0 Move all terms containing p to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1p = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1p = 0 + -1 -1p = 0 + -1 Combine like terms: 0 + -1 = -1 -1p = -1 Divide each side by '-1'. p = 1 Simplifying p = 1

Solution

p = {-2, 1}

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